Table of Contents Table of Contents
Previous Page  809 / 868 Next Page
Information
Show Menu
Previous Page 809 / 868 Next Page
Page Background

T R

G O N O M E T R

~

and an oogl.

o~poli,.

lo o•• of ,h.m being

~iYeo.

'o find

lhe angle oppofi'e 'o ,he o,her.

EXAMPLE . In lh. ,riangle ABC

(ihid.

un

4.)

fuppofe

AB=IS 6. BC=34' .nd ,he angle C (oppofi te ' o AD)=S6°

30'; reqoired Ihe angle A, oppofi,e ' o BC.

2 .

G~oUJ(lrkally :

Draw the line AC, and at any point

of

lt,

foppofe C. make Ihe .ogle

C=S6°

30' ; Ihen I. ke

CH=84, .nd ",i,h Ihe Icng,h of 156 = AB taken in yoor

compafrc:s from the (ame (c¡le of equal parts. fi Jt:ing ane

poio, io B , wi,h ,he o,her crof. AC

ro

A . L,Oly, join

A .od B ; fo ,be tri.ngle i. cooOroaed, and Ibe requi red

angle A may be Olear. red by. line of chord•..

2 .

Bycalcula/io,,:

W.

b.ve

,

hy ,heor.

l.'

,he folJowiDg

proporrioa for 6nding .he angle A,

"i• .

A B : B C :: S. C: S, A.

i .•.

••

AB

IS6

2.' 931 2

To

Be

84

1.924,8

So is

S, C

560

30'

9.921J

1

To

S, A

26°

4"

9.650'1

CASE

Il.

The angles. and

a

fide oppofite lo one of ,hem,

being

giV:A,

to 60d a "de oppofite to another.

EUMPLF.. In ,he triangl. HBG

(ihid.

nO

5.)

~,ppofe

Ihe .agle H 46°

IS',

aDd Ihe angle B 54° ,,'. confequeo,–

ly .I,e angle G 79

n

23', aad ,he leg HB

125.

required

HG.

C.omdrically:

Oraw HB

125.

from .ay line of equal

paru, and make the

~ngle

H 46°

lS',

aod B

54~

'2',

Ihen produce

I~e

line. HG 'Dd BG

tiJl

Ihey meel one .no·

.her in ,he poin. G: fo ,he tri'Dgle is conClroBed , and HG

is·meafured

by

taking

it,

length jo your: compa(fes, and ap

plyio~

il

10

Ihe f.Ole lioe of equal parts .ha! HB was takeo

uken from .

2 .

B} calrola/io,,:

By,he 6rfl of Ihe preeediDg Iheorem.,

we have Ihi, oo. logy for finding HG,

"iz.

S, G : HB:: S, B

: HG.

i .

r.

As Ihe fine of G

7'1°

23'

9.992SO

il'o .he leg HB

125

2'°969 1

fo i. Ihe fine or B

54° ,,'

9.9°996

10

,he leg HG

103-4

2.0143 7

, C....

IIl.

T wo flÓe. ond ao . ogle oppoGle.o ooe of .heID

¡ iveo, to find the third fideo

EXAMPLE. In ,he triangle KLM

(ibid.

o· 6.) fuppofe

Ihe fide CL

126

equal par.. , .nd KM '30 of ,hefe parlS,

.nd Ihe .ngle L (oppofite 'o

KM)

63° 20'. requíred Ihe

lid.

ML.

J.

C,om"rically:

The conllruélion of ,hi. cafe is Ihe

r.me

wilh ,hat in Cafe

l.

(Ihere being Ihe

f.me

,hing. gíven

in bOlh,) .nd ,he leg ML may be meafured by

applyin~

it

tO

the

rame

lioe of equal

parta that the othef two

were

take"

{romo

2.

By cahu/a/ion:

T he folu,ion of Ihis ""fe depends up–

on the r\Vo

preceding onel ;

aud, Grít, w-e muH fiad

the other

tI'O angles

lry

C.fe

1. •

hus:

MK:S,L::KL :S, M.

i . •.

Asthe firle MK

'lo

2.11394

T o .he

r.ne

of L

63°

20'

9 9 5I 16

So i..he fide KL

126

• . 10°37

To .he fine of M

60°

l'

9.93159

Tben by

C.re

11. we ha.e Ihe requi red lec ML, ,hus:

S. L:S. K :: MK:ML.

;.

~.

A,

the fine o{ L

63""

2 0'

To ,be fine of K

53 o 39'

So is KM

130

2. 11 394

To ML

11 7.2

2.068so

CA" IV. Two fideo Ind Ihe con..ioed angle being , iven,

10

find ,he o,her 'wo abgle•.

EXAMPLE: In Ih. frian,le ACO

(ibid.

nO

1.)

fappoCe

AC=lo). AO=126, and Ihe ingle A=S4 ° 30'; required

.he angle. C and O .

l .

C''''/~/rically :

Oraw AO=126, lod make .he anglo

A=54° 30; Iheo fel off 10) equal PI'" from

A

'0

C :

h flll',

join C and O ; and fo the triangle il conClruaed,

'Dd Ihe 'Agles C .nd O

m,'y

be me.fured by. líne of chord•.

2 .

By calctlla/ion:

The folo,ion of Ibis cafe depend• .up .

on the fecond ,nd thírd of Ihe precediRg Iheorem.; .nd fi,lI

\Ve mull find Ihe fum .nd dilference of .he fides. and halr

Ibe fu m of ,he uDkDOWO aDgle., Ih.s:

The leg AO i.

,,6

The leg AC i.

10)

Their fum is

And their difFerence is

The fum of .he Ihree .o¡le. A, O. aod

e,

i.

The In¡le A i.

So Ihe fum or Ihe angle. C Ind O will be

12SO30'

And

h.lf

Iheir fum i.

6, ° 4S'

Then by Iheor. 2. we

h.ve

Ihe following-proportion,

"iz.

As ,he fum or,he fideo AO aDd AC=229

2.359 84

T o .heir di/l'erence

23

1.361 73

So i. Ihe "ogeol

ofh.lf

.he fum of ( 6' -,

88 6

Ihe uDkDOWO aogles C . od O

S

2

45

10.2 1

To tango of

h.lf

Iheir dilference

11

0 . '

9.29"0S

Now huiDg

h.lf

Ihe foOl .nd

h.lf

.he dilfereote of ,he

IWO.unknolO••ogle. C aod

D;

we li.d Ihe q••o,i,y

ofe.ch

of .hem by Iheorcm 3. Ibus:

To half ,he funa uf Ihe ••gles C aod

-O,

"iz.

Add half Iheir difference,

"iz.

And Ihe funa i. Ihe gre.,er .ngle

e

Agaio froAl h. lf their fwn,

"iz.

Take balf Ibei, di/ference,

"¡".

And ,here.wiU

rena.io

.be lelfer angle

o.

N . B. The gre..er .ogle i• •I",.y.

,h"

fubtended by .he

greater fide: tI{u., in the pre(ent care .

the

greater angle

C.

is fualended hy Ihe greater

C.de

AO ;

.04

Ihe lelfer angle

O 'is fub,ended hy ,he lelfer ude AC.

CA" V . Two fides and Ibe contaíned angle b<ingginA,

'o fiod .he Ihird fide-

EX' MPL. .

Io Ihe trilogle RCD

(ibid.

nO

8.)

fuppofe

BC=154, Bo.=I33. aod ,be .ngle H=S6°

03';

required

,he fide CO .

l .

Cto1llclrica/ly:

T he

conllrull:ion of this

ca

re:

¡s

rhe

f.me

\Vilh Ihal of .he

I.CI

••nd ,he lenglh of OC í. found

by taking i.. leng'h in your compotT<s, . nd applying il lO>

the (ame Jine of equal parts thu the:

t \VO

IC8' were u.kcn

rrom.

2 .

By 'trlculaJion:

T he folu,ioo oflhi, c. fe dcpcnds

u~·

on Ihe fecond aod fourth; 'Dd 6rft IVe lIIull 60d Ihe aogles

by .he laCl cafe ; ,hu. :

A••be fum of

,he

fideo DO. and BC 287

2.408g

Is