Table of Contents Table of Contents
Previous Page  438 / 868 Next Page
Information
Show Menu
Previous Page 438 / 868 Next Page
Page Background

N

A

v

1

G

C"tq''''' TRl CA '

LV.

H . ving d ra\\"o ,he compars

NES\V (No ·'7.) let C reprereDt the pi

¿ce

the Chip fai l·

ed from; draw .he SE lioe CA, whi, h make equal tO

.l20;

,heo will A be the place the Chip caped ...

From A draw AB paraJlel to ,he W óN Iioe

cn,

e–

lJ.ual to

40.

the

mOl ion

of

lhe

current in

20 hOU ls.

and

joio CB; theo

B

",iJl be the fl,;p's true place a' .he eod

of 20 hou". CS her "ue elill,oce, ami .he aogle SCB

her (rue courre. T e find which

By

CALCl.t LATl ooN;

lo ,he triaogle ABC, are eiveo CA

,·zo.

AB '40' aod

,he aogle CAB cqual to

34

°

45',

the dlllaoce betweeo

,he EóS . nd SE lines, to Iind tue angles B ao<l C, aod

the Gde CH.

Firfl. For the aogles C and

B,

it \\ iJl be, (by oblique

t rigonometr.y)

As th. fum of ,he Gdcs CA aAd AS 160 -

2.2°4 12

is

10

.heir dilfereoce

80 - 1'90309

fo is ,he tango of half the fum

~

of the angles

B

and C _

5

73°, °7' 10.517 8

3

to the tango of half rheir dilt.

S9 '

4

S 10 .21680

confcqueotly ,he aogle

B

will be 13 1 , 5>, aod the

angle ACB

'4'

23'. Hence ,he true courfe is S 30°,

37' E,

~r

SSE , °.07' eaflerly.

Then for tho true diflance

CH,

it will be,

(by

oblique

trigonome<ry)

AStheGneo(E

13',°,52' -

9 8 71 98

i, .,o AC

1'0

, .07918

ro.i. the .fine o(

A

33 °,45' -

9.744H

to the <rue diflaoce CB

89· 53

1·95 '94

EXAMPLr

I11.

Suppofe a Chipcomiog out from rea in

·the nigb', has fight of SciJly light, bearing NEhN dif·

tance 4 leagues, it beiog then flood lide feuing ENE,

miles an hour

J

and the Ihip running after

lhe

Tate

of 5

",iles an hour. Required upon

wh.aI

courfe and

ho~far

!he mull fail to hit ,he Li-zard, which bear.. (rom 'Scilly

EtS dillaoce 17 leagues.

GEOMETRl CALL.Y.

Havíng drawn (be

compar,

NESW (No. ,8.) Ict A reprefeot ·the Chip's place at fea,

aod draw the NEhN lioe AS, whieh

m.ke

equal tO 12

",ilcs, fo S \\ill rcprefcot.Seilly.

From S dra", SL equal to 5' mile., and parallcl to ,he

E { S line; thcn L will reprcfeot the L izard.

From L draw Le parallel to the EN E line, equal to

, mile., aoel froll1 C draw CO equal to 5 mil.. mee,iog

AL io D ; theo from A draw AH paralld ' o CO meet·

ing LC produc<d in B ; and AB will be

tlie

reqlÍired dif·

taoce, and SAB the "ue courfe. To fiod wh;ch

By

CA'LCULATION;

In the.triangle ASL are giveo the Gde AS equal to

l'

miles. the Gde SL equal ' o

5' ,

and the angle ASL e–

qual 'o 11 80 07', the diflaoee betweeo the NEbN aod

W{N lineo ; to fi nd the angles SA·L . nd SLA. Cbo–

feq ueotly, (by oblique trjgonornctry,) it will be,

A, ,he fum of the Gde. AS and SL

63

¡,

79934

;. 'othei r dilference

39 I.S9, 06

fo i. the

t~og.

of half.the fum

~

300, 6'

• 6

of 'heangle. SAL aod SLA5

S 9,7,7

3

to the tangoof half ,heir dilf.

20°, '1 '

S' .s6935

v.oJ.

. lll . N',

SS.

2

A

T

1

o

N,

coofequentl y the angle SAL, will be

5'''

1", aoa fo the

di" él bearing of the L rzard froOl ,he .Chip will be N

8S"

02' E, or E óN 6° 17 ' E; and for the dillaoce AL, it

wlII be (by oblique trigooometry,)

AsrhellneofSAL -

S1 o, 17'

is

10

SL

SI

fo is rhe uoe of ASL

118

0 ,

07'

'o

AL

57.6S

rhe diClaoce b<tween ,he Chip and .he L izard.

9. 8 9

22

3

1.

70757

9 -94 54'6

1.7 6080

Ag.io

, in .he triangle OLC . aFe giveo the angle Le–

qual

W

17.0 3'" the diflanee be. w«o the ENE and

N

-SSo

o,'

E

lines; the Gde LC, equal to , miles, .he cur–

rc:nCs dri(t in an hour; and [he (ide C O,

~qual

to

S

miles,

,he Chip:s ruo io ,he fat¡le time. H t oce for ,he angle D,

i, wiJl be (by oblique trigonometry,)

As the Chip's ruo iD t hour OC

5

0.69897

i, 'o ,he Gne of L

17°, 3" - 9 ' 4'789t

fo i, ,he curreot's drif, LC

,

0 . 30 t0 3

'o ,he Gne of

D '-- --

6°,

SS' -

908100

coofequently Gnee by coollcullion the angle LAB is cqual

'o .he aogle LOC, the courf. the Chip muClneer is S 880

03'

E.

Then for the diClance AB, i, '\ViII be

(by

oblique tri–

gooometry,)

ASthe

r~oe

of B

155°, 33' -

9.6,689

is to AL

S7·6S

--

1'76080

fois the GoeofL

17 ·3'

94789~

,o

AB

41.96--

1 '~"~5

confequently, Goce the Chip is failing

al

,he ra'e of S mil...

ao hour, it

(011014'$,

.h.. in failiog

8

h

'4"' S 88° 03'

E,

/he will arrive

at

the L ieard .

EXAMPLr

IV. A

Chip from

a

certaio headland in ,he

lati,ude of 34°00' oorth, fail, SEóS " mile. io three

hours. in a current thal Cets berweeD Rorth and

can;

and

then the fame hcadlaod is fouod 'o bear WNW, and ,he

Chip to be io ,he latitude of '33°

S'2'

oOrlh. Required ,he

fcu ing aod drift of .he eurrent.

G EQ METRI CALLY.

Having dra\Vn ,[he

compar,

NESW (No. 29' ) le, A reprdeot the place of the Chip,

and draw the SEhS lioe AB equal

10

1~

miles, alfo the

ESE lioe AC.

Set olffrom A upoo ,he·meridian AO,equal ,o-S miles,

the dilfercnce o( latitude, aDd through O draw OC pa–

ralld

10

the eaCl and.well line W E, mee,ing AC in C .

j oin C aod

n

wi,h the righl line BC; theo C wil: be,he

/hip's .place.•he angle ABC the fetling of ,he curren'

from ,he SE bS line, aod ,he lioe BC will be the drif,

of ,he curreot in 3 hours. To find which

By CALCULATION :

lo the triangle

ADC,

right aoglcd

al

O , are given the

dilteren.ce

of latitude AO equaJ

10

6

miles, . he aogle

D AC <qual tD 6:70 30'. Whence (or AC, the dillaoee

the Ihip has faoled, it will be

As radius

8

10.0~OOO

0·9°3°9

is lO"the diff. o( lati,ude AO

fo i, the fe eaDl of the courfe

~

D AC

_

_

5 - 67° , 30' 1°' 4

1

7 16

lO the diflance ruo AC

20.9 - 1.3'°25

Ag.;n, in the triansle ABC,

are

giv~n

AH

<qual

'o

S E

t

1.7