N
A
v
1
G
T houg1\ tbi. lable does <lnly 1bew tbe mile. anfweriog
10
a degree of aoy paraJld, wbofe btitude confiO. of a
Wlhole Dumbcr of degrees
1-
yet it may be made tO ferve
for
~ny
paralleJ wbofe 'Iatitude is
fo~e oumbe~
of
degree. and mioutes, by OIakiog tbe followmg proporuoo,
~iz.
As
t
d!gree, or 60 minuus, is
lO1.bedifFereoce be–
tweeD
(be
nllJes anfwering tO a
degrce
iD
(he
next greatcr
'snd oex, lef. t.bular Iotitude tbao tba, propofed; fo i.
the excefs of the propofed latitude above the next tabular
J¡titude, to a proponional part
j
which, fubtrallcd (rom
(he miles iofwcriog
lO
a degree
óf JOogilude
in (be ncxt
Jef.· tabular latitude, will give tbe mil.. aofweriog to a
degr<e io tbe propofed latltude.
EXA MPLt , Required to find ,he mile. aofwering to a
degree on the paral/e1 of
56° 44'.
Fir(t, The oex' I.f. parallel of laritade io the table
Ihao Ihat propofed, i. tha. of 56° , a aegree of which (by
.he .able) i. equat to
33 .55
mile.; aod tbe oex' greater
parallel of latitude in the table. thao that propoled. is
thal of
57°.
a degree of which is (by tbe uble) equal to
3' 68 miles
¡
lbe diCIerence of thefe is 87. and the
dillance betwcen theCt parallc::ls is
I
degrce or 60 minutes;
alfo Ihe diOance be.",eeo the par. UeI of 56°. and the
propofed paraUd of 56°
44',
i.
H
miou«s : theo by Ihe
precedi0l: proportioo it wiU be. As
60
i. to 87. fo is
44 to
638,
the diIFerence betw..n a degree on the paral·
Id of
56°
aod a degree
o~
lhe parallel of
,6°
44'; which
Iherefore t. keo from 33.55, the milesanfwering tO a de·
greo
on the paraUel of
56°.
leaves
3'.9".
the mil..
anfwering to a degre. on tbe paraJlel of 56°
44' .
as was
rcquired.
CA SE Ir. The diOance failed in any p.raUd of lati·
lude, or lhe dWance between any
two
places
on
that pa·
ralle!. being given; tO find the diIFereDce of longitude.
EX'MPLE. Suppofe • Chip in the Iatitude of
15° 36'
nonh fails direéll
y
ean 685 6 miles: required how mucb
Ibe has dlIF.red her longitude.
By Coro4 . Art.
l .
of this feélioo. il wiU be
Asthcco fioeof the lal. --
15°
36' --
9.75202
is to
radius
10.00000
fo is the diO,oce f.iled
--
685
6 --
283607
10
,,!in. of ditf. of long.
1213 -- 3..08405
"hich rtduced into degree., by dividing by
60.
mak..
20° 13'.
the d,IFerence of longi,ud. the Chip has made.
This may alfo be folved by help of the foregoiog
table,
viz.
by finding
from
it
lhe
miles anrwering
to
a degree on ,I¡e propofed par.llel, aod diVJdiog with
this che
giveb
number o( miles, the quotient will be
' lje degree. and minule. of dilference of loo¡itude re·
qoired.
Thu, io Ihe I.n example
¡
1 find. from the fo.-going
table. that a degree on the paralle! of
55°
36'
i. equal
lo
33 89
miles;
' y
this
1
di.ide Ihe propofed number of
mil..
685.6
aod tlle quotieot i.
20.13
degrees;
i.
e.
20°
) 3', the
dífFertnce of
longitude
required.
CAS E IIl. The diIFereoce of loogitude
belw.enI\VO
place.
00
the fame paralle!. aod Ihe diOance belweeo
tbem. being given;
10
find
,1"
latilude of thal p.raUel.
EXAMPLE . Suppofe a Chip fail. on a c",tain paraUd
direélly wcll
6.24
miles, aod then
Iu.
differed her loogi.
A
T
1
o
N.
37 3
lude
18° 46'
or I 126 miles·: Requircd Ihe
IMit.deof
Ihe paraUd Che f. iled upoo.
By Coro
3.
Art.
l .
of ,hi. feélion, il will be,
A"be mino
ef
d.IF. long.
11 16
3.oPH
is to ,he diO.nce failed
624
2:795 18'
fo is
radius
J
0.00000
10
Iheco fine oflbelal.
56°
21' -
9.743
64
confequeotly the latitude of the Ibip or par.Uel Che 'failec!
upon was
.5
6°
21'.
From wh.. bas b«o faid, m.y be [olved
Ibe
foUo'Ning
proble., ..
PROB o
1.
Suppofe Iwo Chips in theJatitUde of
46°
30'
oonh.
diCI.nt.funder
654
míle._ fail both direélly no"h
256
miles, and confeque.ntly are come tO Ihe lalitud.
of
50'
46'
oonh : R equired their
d;n.o~e
on Ibat paraJltI
By Cor.
6.
Art.
1,
of Ihi. Seétioo, il will be.
As the ro fine of
46'
30'
9.8 37 81
is to the co·lioe of
50° 46'
9,80105
foi.
654
2,81158
to
601
2.77882
the diOance betweeo the Chips \Vheo on the paraUeI of
50° 46' .
PRO'. Il. Suppofe IWO Chip. io the latitude of
45
0
4 8'
north.
diO.nl846
miles. f,iI dircélly north tiU Ihe dif,
tance bel""'eo Ihem is
624
miles: Required the lalitudc
come
10.
ond
I~e
diOance failed .
By Coro 5. Art.
l .
of this Seélioo, it wiU be,
A. Iheir firll diOance
846
2 '9 2 737
i. to their fecood diOance -
624
2.79$18
fo i. the co·fine of -
145
o
48'
9.84334>
tO Ihe co·fine
-
59. 04
-
9.711
IS
lhe latitude of Ibe paraUd the Ibips are come
10.
Confequently tO find th';r dillaoce failed,
From
[he huitUde
come
tO
fubtr.élthe I.tilude f.iled from,
2nd
there remaini
-
-
13
t
.6
_qual to
796
mile., Ihe d¡IFereDce of
L ..
ilude or dlllaoce
f.,led.
Seft. 4. Oj'MIDDLE'LAT'TUDE SAILINC.
WHEN tWO places lie both on the fame ",rallel.
we
(hewed in the laO feéliQn, how, from the diIFerence of
longitude given. tO 60d Ihe miles of e.Uing or welling
between
lbem,
&
e con/rll.
But
when
two
places
lie
not
on the fame par.Uel. then tbeir diIFerence 'of longilude
canoOI
be
rtduced
to
miles
or
ea(liog
or
werting on
the
pa.
r.U<I of eith.. place: for ifcounled on the par. lid of tb.l
place that has Ihe greateO
latit.de.it would be loo fmall ;
~tn;~~I~o~~~::~~~:~.o~~~~~ltahc: ~~,i;~~~~~;·o(lflr:I~~Uc~:~
the difl'ereoce of longitude belw«n IWO places: l)'ing on
diIFerent p.rallds.
10
miles of c.Oing or wemog,
&
~
t Ol1lra·,
is
by counting ir
00
the
middle paralJel
between
the places,. which is found by adding Ihc latitudes of Ihe
IWO
pl.ce.together. aod taking half ,he fum, whicb
",iII
be Ihe I.tilude of the middle par.Uel required. Aod
hcnce arifes <.he folution of Ihe following cafes.
CA! E
1.
The latiludes of two places. and their dif,
ference of longitude, giveD;
10
find Ihe direél courfe aDd
dill.oce.
EUMPU.